were going to have a negative log base 2 of x. Develop a t-chart if you want to fill in any other values. Well, the obvious thing that jumps out at me is that its flipped over the x-axis, so thats a pretty good sign that this is going. Plot a vertical dashed line at x = 4, plot your intercepts and sketch the graph, understanding that the value of the function falls from left to right. We will use point plotting to graph the function. To figure this out, it's helpful to rearrange the equation in a different form. Solution: To graph the function, we will first rewrite the logarithmic equation, y log2(x), in exponential form, 2y x. The x-intercept is the value of x when y = 0. The log function can be graphed using the vertical asymptote at x 0 x 0 and the points (1,0),(2,1),(4,2) ( 1, 0), ( 2, - 1), ( 4, - 2). Therefore, we should understand that the function decreases from the left, and falls asymptotically at x = 4. We can also understand that the behavior of the function is opposite of its parent function, log(x), since we effectively have log(-x). However, to simply sketch the graph, we need some intercepts and an understanding of the graph's behavior via asymptotes.įirstly, we should understand the function is asymptotic at x = 4, since the log(0) = inf. The log function can be graphed using the vertical asymptote at and the points. You can certainly create a t-chart and evaluate the function for various x-values. Set the argument of the logarithm equal to zero.
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